Per Unit System: 4 Brilliant Shortcuts for Fault Studies

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Power Systems
Per Unit System: 4 Brilliant Shortcuts for Fault Studies

Expressing every quantity as a fraction of a chosen base turns messy multi voltage networks into simple arithmetic.

Base MVA Base Impedance Change of Base Short Circuit

The per unit system expresses voltages, currents, powers and impedances as fractions of chosen base values. It removes transformer ratios from network calculations and makes fault studies far easier.

Hello everyone, today we are going to learn the per unit system, how to choose base values, how to change impedance from one base to another and how to use it for a quick fault calculation.
per unit system

What Is the Per Unit System?

The per unit system is a method of expressing electrical quantities as a ratio of their actual value to a selected base value. A voltage of 10.45 kV on an 11 kV base becomes 0.95 pu, and an impedance is expressed the same way against a base impedance.

Two base values are chosen freely, usually power in MVA and voltage in kV. All other bases, such as current and impedance, follow from these two.

Formula for changing per unit impedance from an old base to a new base
Image credit: Electrical PE Review

Nameplates already use this idea. A transformer marked 8 percent impedance simply has 0.08 pu impedance on its own rating.

Engineers use per unit values in every load flow and short circuit program. Understanding them makes the software results much easier to check.

Base Quantities and Formulas

Choose Base MVAOften 100 MVA for the whole network
Choose Base kVRated voltage in each zone
Base CurrentMVA ÷ (√3 × kV)
Base ImpedancekV² ÷ MVA
Per Unit ValueActual ÷ Base

Base MVA is the same everywhere in the network. Base kV changes across each transformer in proportion to its turns ratio, which is the trick that removes ratios from the calculation.

Three phase formulas use line voltage and total power, so the √3 terms appear only in the base current. This avoids the usual confusion described in three phase power calculation.

4 Brilliant Shortcuts of Per Unit Analysis

1
Transformers Disappear
Per unit impedance is the same from either side, so ratios vanish.
2
Values Fall in Narrow Ranges
Machine impedances cluster, which helps spot data errors.
3
Simple Fault Current
Fault current in pu is simply 1 divided by total pu impedance.
4
No √3 Confusion
Single phase and three phase results match in per unit.

Shortcut 2 is useful for sanity checks. Transformer impedances usually fall between about 4 and 15 percent, so a value of 80 percent suggests a typing error.

Shortcut 3 makes hand checks of short circuit current quick and reliable before running software.

Change of Base Formula With Example

Z base = kV² ÷ MVA
Z pu new = Z pu old × (MVA new ÷ MVA old) × (kV old ÷ kV new)²

Worked example:
Transformer 10 MVA, 11 kV, Z = 8 percent = 0.08 pu on own base
System base 100 MVA, same kV
Z pu new = 0.08 × 100 ÷ 10 = 0.8 pu

Fault at the transformer terminals, infinite source:
I fault = 1 ÷ 0.08 = 12.5 times rated current
Rated current = 10 MVA ÷ (√3 × 11 kV) = 524.9 A
I fault ≈ 6.56 kA

The change of base step is needed whenever equipment ratings differ from the common system base. Skipping it is the most common per unit mistake.

Real fault levels are lower because the source impedance adds to the transformer impedance. Add all pu impedances on the same base before dividing.

Typical Per Unit Impedances

EquipmentTypical Impedance on Own RatingNotes
Distribution transformerAbout 4 to 6 percentLower value, higher fault level
Power transformerAbout 8 to 15 percentChosen to limit fault current
Generator subtransientAbout 10 to 25 percentDecides first cycle fault current
Induction motor locked rotorAbout 15 to 20 percentMotors feed fault current too
Cables and linesDepends on lengthConvert from ohms per km

These ranges help build quick estimates when data is missing. Always replace them with nameplate or test values for final studies.

Transformer impedance also sets how much voltage drops under load, linked to the turns ratio and secondary voltage.

Where the Per Unit System Is Used

Short Circuit Studies
Fault current and breaker rating checks.
Load Flow
Voltage profile and line loading.
Relay Settings
Converting fault levels to relay secondary values.
Motor Starting
Voltage dip during large motor starts.
Stability Studies
Generator angle and swing analysis.
Equipment Data
Nameplate impedance and reactance values.

Relay engineers turn per unit fault levels into relay currents for coordination studies.

Transformer selection uses the same data, including kVA rating from transformer kVA calculation.

Common Mistakes in the Per Unit System

Mixing values on different MVA bases without conversion is the classic error. Always write the base next to every pu value in your calculation sheet.

Another error is using the wrong kV base across a transformer. If the transformer ratio differs from the nominal kV ratio, use the voltage correction term in the change of base formula.

Finally, remember to convert results back to amps, volts or ohms at the end. A per unit answer alone means nothing to the person choosing a breaker.

Fault Current Calculator

Transformer Terminal Fault
Result
Rated 524.9 A, fault 6.56 kA, Zbase 12.100 ohms

This result assumes an infinite source. Add source impedance in per unit on the same base for a realistic value.

Advantages
  • Removes transformer ratios from calculations.
  • Makes data errors easy to spot.
  • Simplifies fault and load flow studies.
  • Same values on both transformer sides.
Things to Watch
  • All values must share one MVA base.
  • kV bases must follow transformer ratios.
  • Convert back to real units at the end.
  • Nameplate percent must be converted to pu.

Per Unit Representation Chapter PDF

PDF
Chapter 1, Per Unit Representation
Book chapter on base values, change of base and network modelling

Per Unit Values Explained on Video

Per Unit System FAQ

What is the per unit system?
A way to express electrical values as fractions of chosen base values.
Which bases are chosen freely?
Usually base MVA and base kV.
What is base impedance?
kV squared divided by MVA.
Why do transformer ratios disappear?
Base kV changes with the turns ratio, so pu impedance is the same on both sides.
How is fault current found in pu?
Divide 1 by the total per unit impedance.
What does 8 percent impedance mean?
0.08 pu on the transformer own rating.
Do I need to change base?
Yes, whenever equipment ratings differ from the system base.

Related Articles

External References

What We Learn Today

  • Pick base MVA and base kV, then derive base current and impedance.
  • Change every impedance to the common base before combining.
  • Fault current in pu is 1 divided by the total pu impedance.
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