Voltage Drop Calculation for Long Cable Runs: Formula, Examples and Calculator

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Electrical Design & Calculations
Voltage Drop Calculation for Long Cable Runs: Formula, Examples and Calculator

When a cable runs over a long distance, voltage at the load end is always lower than at the source. If the drop is too large, motors lose torque, instruments give wrong readings, and the cable itself runs hotter than designed.

This guide covers the full calculation procedure for DC, single phase, and three phase circuits, with two worked examples and an interactive calculator for all three circuit types.

IEC 60364 Limits 3-Phase Formula mV/A/m Method IEC 60228 Table

Every electrical installation has a maximum allowable voltage drop defined by its applicable standard. IEC 60364 limits voltage drop to 3% for lighting and 5% for other loads. Exceeding these limits is one of the most common commissioning failures in industrial plants.

What Is Voltage Drop and Why It Matters

Voltage drop is the reduction in voltage along a cable caused by the resistance of the conductor. When current flows, the conductor's resistance consumes a portion of the supply voltage before the remaining voltage reaches the load.

Voltage Drop Calculation

This is a direct application of Ohm's Law: voltage lost across a conductor equals the current multiplied by the conductor resistance (V = IR). For a long cable, that resistance is significant enough to matter.

The two variables that most affect voltage drop are cable length and current. Doubling the cable length doubles the drop. Doubling the current also doubles the drop. The only way to reduce both is to increase the conductor cross sectional area, which lowers resistance.

In process plants, the practical consequences of excessive voltage drop include:

  • Motors running at lower speed than rated, with reduced torque and higher slip
  • Contactor coils that fail to pick up or drop out at incorrect setpoints
  • 4 to 20 mA loop powered instruments losing accuracy at the far end of long runs
  • Overheating in the cable from power being dissipated as heat
  • Nuisance tripping of thermal overloads and contactors. The power factor correction guide covers how reactive current compounds the drop in motor circuits
3%
IEC 60364 limit for lighting circuits
5%
IEC 60364 limit for motor and other loads
×1.24
Resistance correction factor from 20°C to 70°C (PVC cables)
√3 = 1.732
Three phase factor replacing the factor 2 used for single phase
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The Voltage Drop Formula: Three Versions

The correct formula depends on the circuit type. There are three cases: DC, single phase AC, and three phase AC.

For most practical low voltage calculations, the simplified resistive formula is sufficient. For longer runs or inductive loads, the full impedance method is used.

DC Circuits and Resistive AC Loads

For DC circuits and short AC runs where reactance is negligible (power factor close to 1), the formula is:

DC / Single Phase Resistive Formula
Vdrop = 2 × I × L × R
Vdrop = Voltage drop (V)
I = Load current (A)
L = One way cable length (m)
R = Cable resistance per metre (Ω/m), from IEC 60228 or cable datasheet

The factor 2 accounts for both the line conductor and the return (neutral) conductor.

Cable resistance values are published in cable manufacturer datasheets and in IEC 60228. A typical 2.5 mm² copper conductor has a resistance of approximately 7.41 mΩ/m at 20°C, rising to around 9.18 mΩ/m at the maximum operating temperature of 70°C (PVC insulation).

Single Phase AC Circuits

For single phase AC, reactance starts to matter when cable runs exceed roughly 50 m at LV. The IEC and BS 7671 method uses the mV/A/m value from the cable manufacturer's table:

Single Phase AC Formula -- mV/A/m Method
Vdrop = (mV/A/m × I × L) ÷ 1000
mV/A/m = Voltage drop per ampere per metre (from cable datasheet)
I = Design current (A)
L = One way cable length (m)
1000 = Converts millivolts to volts

Three Phase AC Circuits

For balanced three phase AC circuits, the formula uses the √3 factor because voltage drop appears line to line and the neutral carries no current in a balanced system:

Three Phase AC Formula
Vdrop = √3 × I × L × R ÷ 1000
√3 = 1.732 (three phase factor)
I = Line current (A)
L = One way cable length (m)
R = Conductor resistance per km (Ω/km) from the cable datasheet
1000 = Converts Ω/km to Ω/m

Using mV/A/m method: Vdrop = (mV/A/m × I × L) ÷ 1000 -- the √3 factor is already embedded in the three phase column of the manufacturer's table.

Percentage Voltage Drop: The Compliance Check

The absolute voltage drop in volts is useful for design, but standards limit voltage drop as a percentage of nominal supply voltage. This is the number inspectors check.

Percentage Voltage Drop V_drop% = (V_drop / V_supply) × 100
StandardCircuit TypeMax Allowable Drop
IEC 60364-5-52Lighting3%
IEC 60364-5-52Other loads (motor, heat, etc.)5%
BS 7671 (public supply)Lighting3%
BS 7671 (public supply)Other circuits5%
BS 7671 (private supply)Lighting6%
BS 7671 (private supply)Other loads8%
NEC (NFPA 70)Branch circuit3% recommended
NEC (NFPA 70)Feeder + branch total5% combined
AS/NZS 3000 (Australia)General5%
In Indian industrial plants referencing IS 732 or IEC practice, the 5% limit for motor feeders and the 3% limit for instrument and lighting circuits are the standard benchmarks used in design and commissioning.
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Worked Example 1: Three Phase Motor Feeder (IEC Method)

This is the most common calculation in industrial plants. A 415V three phase motor sits 150 m from the panel, drawing 85 A.

Cable: 25 mm² copper, 3-core PVC, R = 0.780 Ω/km at 70°C (from the manufacturer's datasheet).

Worked Example 1
Three Phase Motor Feeder: 415 V, 85 A, 150 m, 25 mm² Copper
1
Identify the resistance of the cable. From the datasheet: R = 0.780 Ω/km at 70°C.
2
Apply the three phase voltage drop formula: Vdrop = 1.732 × I × L × R ÷ 1000
3
Substitute values: Vdrop = 1.732 × 85 × 150 × 0.780 ÷ 1000
4
Calculate step by step: 1.732 × 85 = 147.22 → × 150 = 22,083 → × 0.780 = 17,225 → ÷ 1000 = 17.23 V
5
Calculate percentage: Vdrop% = 17.23 ÷ 415 × 100 = 4.15%
Result: 17.23 V drop = 4.15%  |  Within the IEC 5% limit for motor loads. Cable is acceptable.

If the result had exceeded 5%, the next step would be to upsize the cable to 35 mm² (R = 0.554 Ω/km) and recalculate, which would bring the drop down to approximately 2.95%.

Worked Example 2: Single Phase Lighting Circuit

A single phase 230V lighting circuit runs 80 m from the distribution board, carrying 16 A.

Cable: 4 mm² copper, mV/A/m = 11 from the BS 7671 voltage drop table at 70°C.

Worked Example 2
Single Phase Lighting: 230 V, 16 A, 80 m, 4 mm² Copper
1
Identify mV/A/m from cable table: 11 mV/A/m for 4 mm² single phase copper at 70°C.
2
Apply the mV/A/m formula: Vdrop = mV/A/m × I × L ÷ 1000
3
Substitute: Vdrop = 11 × 16 × 80 ÷ 1000 = 14,080 ÷ 1000 = 14.08 V
4
Percentage: Vdrop% = 14.08 ÷ 230 × 100 = 6.12%
Result: 6.12%  |  Exceeds the IEC 3% limit for lighting circuits. Cable must be upsized.

Upsizing to 10 mm² copper (mV/A/m = 4.4 mV/A/m) gives: 4.4 × 16 × 80 ÷ 1000 = 5.63 V = 2.45%. This is now within the 3% limit.

Copper Conductor Resistance: IEC 60228 Reference Table

Use the 70°C column for PVC insulated cables and multiply 20°C values by 1.30 for XLPE cables at 90°C. For aluminium conductors, multiply copper resistance by approximately 1.64. See the earth conductor sizing guide for IEC 60364 selection rules.

Cable Size (mm²)Resistance at 20°C (Ω/km)Resistance at 70°C (Ω/km)Typical Use
1.512.1015.00Lighting, control wiring
2.57.419.18Power outlets, small loads
44.615.72Lighting distribution, small motors
63.083.82Motor feeders up to 5 kW
101.832.27Motor feeders up to 10 kW
161.151.43Motor feeders up to 16 kW
250.7270.780Motor feeders up to 25 kW
350.5240.554Motor feeders up to 37 kW
500.3870.420Feeder cables, large motors
700.2680.332Feeder cables, very large motors
950.1930.247Main distribution feeders
1200.1530.196Main distribution feeders
1500.1240.159Busbar risers and transformer feeds

Interactive Voltage Drop Calculator

Voltage Drop Calculator
DC, Single Phase AC and Three Phase AC -- IEC method
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Effect of Cable Length on Voltage Drop

This table shows how voltage drop changes with length for a 415V three phase motor drawing 50 A, using 16 mm² copper cable (R = 1.43 Ω/km at 70°C). It shows the point where upsizing becomes necessary.

One Way Length (m)V_drop (V)V_drop%Status vs 5%Action
506.21.5%PASSNo action
10012.43.0%PASSNo action
15018.64.5%PASSNo action
17521.75.2%FAILUpsize to 25 mm²
20024.86.0%FAILUpsize to 25 mm²
25031.07.5%FAILUpsize to 35 mm²
30037.29.0%FAILUpsize to 50 mm²
At 175 m, 16 mm² just exceeds the limit. Switching to 25 mm² (R = 0.780 Ω/km) at 175 m gives a drop of 12.5 V = 3.0%, comfortably within the 5% limit with margin for future load growth.

Voltage Drop in Instrument Cable Runs: A Different Concern

For 4 to 20 mA instrument loops, voltage drop works differently. Long cable runs raise loop resistance, which limits the maximum output voltage a transmitter can develop across the loop.

The maximum loop resistance a transmitter can tolerate is published in its datasheet as a compliance voltage specification. For a transmitter with 17.4V compliance:

Maximum 4 to 20 mA Loop Resistance R_max = (V_compliance - V_min) / I_max V_compliance = Transmitter compliance voltage (V) V_min = Minimum supply voltage at transmitter terminals (V) I_max = 0.020 A (20 mA full scale)

The total loop resistance (cable resistance + barriers + DCS input impedance) must stay below this limit. See the electrical calculations guide and the MCB rating calculation article and the short circuit current article for related calculation methods used in the same design workflow.

6 Practical Rules for Keeping Voltage Drop Under Control

Rule 1
Always calculate at full load current
Use the design current, not the rated cable ampacity. The drop at full load is what matters for compliance.
Rule 2
Use operating temperature resistance values
Resistance at 70°C is 24% higher than at 20°C. Always use the temperature corrected value from the datasheet.
Rule 3
Enter one way length, not loop length
The factor 2 or 1.732 already accounts for both conductors. Enter the one way distance from panel to load only.
Rule 4
Check cumulative drop for instrument loops
For 4 to 20 mA loops, total loop resistance (cable + barriers + input impedance) must stay within the transmitter compliance voltage specification.
Rule 5
Upsize neutral for non linear loads
In circuits feeding VFDs and rectifiers, third harmonic currents add in the neutral. The neutral may carry more current than the phase conductors.
Rule 6
Verify with a loop tester at commissioning
Calculate before installation, then measure after. A milliohm meter confirms actual resistance and reveals high resistance joints or wrong cable pulled.

Watch: Voltage Drop Calculation Step by Step

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Voltage Drop Calculation Questions

Why does single phase use factor 2 but three phase uses 1.732?
Single phase current flows through both line and neutral, so both contribute resistance (factor 2). In a balanced three phase system, the neutral carries no current, and the √3 factor comes from the line to line voltage geometry.
What happens if voltage drop is too high?
Motors get lower torque and higher operating current, leading to overheating. Lighting dims. Instrument transmitters may lose compliance voltage margin, making 20 mA unreachable. Cables also run hotter than designed.
Does power factor affect voltage drop?
Yes for inductive loads. For LV runs up to 100 m at 415V, the simplified resistive formula is generally acceptable. For longer runs or MV systems, the full impedance method including cable reactance should be used.
When should I use the mV/A/m method vs the resistance formula?
Use mV/A/m when the manufacturer's BS 7671 or IEC tables are available -- it is faster. Use the resistance formula when calculating from first principles or applying custom temperature corrections.
Is voltage drop the same as voltage loss?
Yes. The terms are interchangeable. Some standards say "volt drop," others say "voltage loss," but all refer to the reduction in voltage between source and load due to cable resistance.

External References

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What We Learn Today

  • V_drop = 2 × I × L × R / 1000 (single phase/DC); factor 1.732 for three phase
  • IEC 60364: 3% limit for lighting, 5% for other loads
  • Always use resistance at operating temperature -- 70°C for PVC, 24% higher than 20°C
  • Enter one way length -- the factor 2 or 1.732 already accounts for both conductors
  • Instrument loops check compliance voltage, not percentage voltage drop
  • Doubling cable length doubles the drop -- upsize conductor cross section to compensate
“A calculation done before installation is a problem prevented. A voltage drop found after commissioning is a project delay.”

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